Quant in SNAP 2020 Paper Part 2

Q1. Total number of students in class B is 25% less than that of class A and the ratio of the number of boys in class A and B is 5:4 respectively. If the number of girls in class A and B is 60 and 40 respectively, then find the total number of students in class A?

  1. 180
  2. 140
  3. 120
  4. 160
EXPLANATION

Answer: D

Let the total number of students in class A=4x

And the total number of students in class B=3x

The number of boys in class A=5y

The number of boys in class B=4y

4x-5y=60   — (1)

3x-4y=40   — (2)

(1)*3-(2)*4

12x-15y=180

-12x+16y=-160

y=20

x=40

Total number of students in class A=4*40=160

Q2. Ratio of the income of A and B is 6:5 and the ratio of the savings of A and B is 3:1. If the expenditure of A and B is Rs.12000 and Rs.16000 respectively, then find the difference between the income of A and B?

    A.Rs.3000

    B.Rs.5000

    C.Rs.6000

    D.Rs.4000

EXPLANATION

Answer: D

(6x – 12000)/(5x – 16000) = 3/1

15x – 48000 = 6x – 12000

x = Rs.4000

Q3. 360 sweet boxes are distributed among A, B and C. If the ratio of the number of sweet boxes distributed to A and C is 12:11 and the number of sweet boxes distributed to B is 8.33% more than that of A, then find the difference between the number of sweet boxes distributed between B and C?

     A. 20

     B.  50

     C.  80

     D. 70

EXPLANATION

Answer: A

Le the number of sweet boxes distributed by A=12x

And the number of sweet boxes distributed by C=11x

The number of sweet boxes distributed of B=12x*13/12=13x

Required difference=360*(13x-11x)/36x=360*2/36=20

Q4. Average weight of five persons is 51 kg and each of them in different weights. If the average weight of heaviest and lightest persons is 52 kg and the average weight of second heaviest and fourth heaviest persons is 48 kg, then find the weight of the third lightest person?

  1. 63 kg
  2. 48 kg
  3. 32 kg
  4. 55 kg
EXPLANATION

Answer: D

Weight of third lightest person=x

51*5=52*2+48*2+x

255-200=x

x=55 kg

Q5. A’s income is 120% of B’s income and C’s income is 80% of A’s income. If the average income of A, B and C is Rs.3950, what is C’s income?

  1. Rs.3200
  2. Rs.3400
  3. Rs.3600
  4. None of these
EXPLANATION

Answer: C

A = 120/100 * B

A/B = 6/5

C = 80/100 * A

C/A = 4/5

A:B:C = 30:25:24

A + B + C = 3950 * 3 = 11850

C’s income = 24/79 * 11850 = 3600